Which values satisfy the equation cos x = 0?

To determine which values satisfy the equation ( \cos x = 0 ), we need to consider the angles at which the cosine function equals zero.

In trigonometry, the cosine of an angle is zero at odd multiples of (\frac{\pi}{2}) radians or (90^\circ). This means that cosine is zero at angles like (90^\circ) and (270^\circ). Mathematically, you can express these angles in degrees as:

• (x = 90^\circ + k \cdot 180^\circ), where (k) is an integer.

This gives us the angles:

• For (k = 0): (x = 90^\circ)

• For (k = 1): (x = 270^\circ)

• For (k = -1): (x = -90^\circ) (which is equivalent to (270^\circ) on a unit circle)

• For (k = -2): (x = -270^\circ) (which is equivalent to (90^\circ))

Thus, the values that satisfy ( \cos x = 0 ) indeed include